Electric potential energy

Electric potential energy, or electrostatic potential energy, is a potential energy (measured in joules) that results from conservative Coulomb forces and is associated with the configuration of a particular set of point charges within a defined system. Not to be confused with the term electric potential (measured in volts), the term "electric potential energy" is used to describe the potential energy in systems with electric fields that change with time (time variant), while the term "electrostatic potential energy" is used to describe the potential energy in systems with electric fields that do not change with time (time invariant).

Contents

Definition

The reference zero is usually taken to be a state in which the individual point (test) charges are very well separated ("are at infinite separation") and are at rest.[1]:§25-1

One point charge

For one point charge q in the presence of an electric field E due to another point charge Q, the electric potential energy is defined as the work done to bring it from the referance position rref to some position r: mathematically this is a line integral [2]. The electrostatic field is conservative, and for one point charge radial, so it is path independent and equal to the differance in potential between the two endpoints the charge has moved. Mathematically:

 U_E(r_{\rm ref}) - U_E(r) = -W_{r_{\rm ref} \rightarrow r } = -\int_{{r}_{\rm ref}}^r \mathbf{F} \cdot \mathrm{d} \mathbf{r} = -q \int_{{r}_{\rm ref}}^r \mathbf{E} \cdot \mathrm{d} \mathbf{r} \,\!

where:

Usually UE is set to zero when rref is infinity:

 U_E (r_{\rm ref}=\infty) = 0 \,\!

so

 -U_E(r) = -\int_\infty^r \mathbf{F} \cdot \mathrm{d} \mathbf{r} = -q \int_\infty^r \mathbf{E} \cdot \mathrm{d} \mathbf{r} \,\!

Since E and therefore F, and r, are all radially directed from Q, F and dr must be antiparallel and so

 \mathbf{F} \cdot \mathrm{d} \mathbf{r} = |\mathbf{F}| \cdot |\mathrm{d}\mathbf{r}|\cos(\pi) = - F \mathrm{d}r \,\!

using Coloumb's law:

 F = \frac{1}{4\pi\varepsilon_0}\frac{qQ}{r^2} \,\!

allows the integral to easily be evaluated:

 U_E(r) = -\int_\infty^r \mathbf{F} \cdot \mathrm{d} \mathbf{r} = -\int_\infty^r \frac{1}{4\pi\varepsilon_0}\frac{qQ}{r^2}{\rm d}r = \frac{1}{4\pi\varepsilon_0}\frac{qQ}{r} \,\!

Sometimes the factor ke called Coulomb's constant is used in these expressions. In SI units, the Coulomb constant is given by

 k_e = \frac{1}{4 \pi \varepsilon_0} ,

in turn \varepsilon_0 is the electric constant.

Many point charges

The electric potential energy of a system, UE, relative to the chosen zero of potential (position where potential is zero), is defined equal to the total work W that must be done by a hypothetical external agent to bring the charges slowly, one by one, from infinite separation, to the stated system configuration.

In this process the external agent provides or absorbs any relevant work, and the point charge being slowly moved gains no kinetic energy. Sometimes reference is made to the potential energy of a charge in an electrostatic field. This actually refers to the potential energy of the system containing the charge and the other charges that created the electrostatic field.[1]:§25-1

Electrical energy is energy newly derived from electrical potential energy. When loosely used to describe energy absorbed or delivered by an electrical circuit (for example, one provided by an electric power utility) "electrical energy" refers to energy which has been converted from electrical potential energy. This energy is supplied by the combination of electric current and electrical potential that is delivered by the circuit. At the point that this electrical potential energy has been converted to another type of energy, it ceases to be electrical potential energy. Thus, all electrical energy is potential energy before it is delivered to the end-use. Once converted from potential energy, electrical energy can always be described as another type of energy (heat, light, motion, etc.).

To calculate the work required to bring a point charge into the vicinity of other (stationary) point charges, it is sufficient to know only (a) the total field generated by the other charges and (b) the charge of the point charge being moved. The field due to the charge being moved and the values of the other charges are not required. Nonetheless, in many circumstances it is mathematically easier to add up all the pairwise potential energies (as below).

Electrostatic potential energy stored in a configuration of discrete point charges

The mutual electrostatic potential energy UE of two charges is equal to the potential energy of a charge in the electrostatic potential generated by the other. That is to say, if charge q1 generates an electrostatic potential Φ1, which is a function of position r, then

U_\mathrm{E} = q_2 \Phi_1(\mathbf r_2).

Doing the same calculation with respect to the other charge, we obtain

U_\mathrm{E} = q_1 \Phi_2(\mathbf r_1).

This can be generalized to give an expression for a group of N charges q1, q2 ...qN at positions r1, r2...rN respectively:

U_\mathrm{E} = \frac{1}{2}\sum_{i=1}^N q_i \Phi(\mathbf{r}_i)

where, for each i value, Φ(ri) is the electrostatic potential due to all point charges except the one at ri.

NB: The factor of one half accounts for the 'double counting' of charge pairs. For example, consider the case of just two charges.

One point charge

The electrostatic potential energy of a system containing only one point charge is zero, as there are no other sources of electrostatic potential against which an external agent must do work in moving the point charge from infinity to its final location. One should carefully consider the possibility of the point charge interacting with its own electrostatic potential. However, since such a potential at the location of the point charge itself is infinite, this "self-energy" is intentionally excluded from an evaluation of the total (finite) electrostatic potential energy of the system. Moreover, one may argue that since the electrostatic potential due to the point charge itself provides no work in moving the point charge around, this interaction is unimportant for most purposes.

Two point charges

Consider bringing a second point charge, q, into its final position in the vicinity of the first point charge, Q1. The electrostatic potential Φ(r) due to Q1 is

 \Phi(r) = k_e \frac{Q_1}{r}

Hence we obtain, potential energy of q in the potential of Q as

U_E = \frac{1}{4\pi\varepsilon_0} \frac{q Q_1}{ r_1 }

where r1is the separation between the two point charges.

The electrostatic potential energy is negative if the charges have opposite sign and positive if the charges have the same sign. Negative mutual potential energy corresponds to attraction between two point charges; positive mutual potential energy to repulsion between two point charges.

Three or more point charges

The electrostatic potential energy of q due to two charges Q1 and Q2 should not be confused with the electrostatic potential energy of the system of three charges, because the latter also includes the electrostatic potential energy of the system of the two charges Q1 and Q2.

For three or more point charges, the electrostatic potential energy of the system may be calculated by the total amount of work done by an external agent in bringing individual point charges into their final positions one after another.

NB: Here, \scriptstyle \varepsilon_0 is the relative permittivity of free space. When the charge is in a medium other than free space or air, the relative permittivity

\varepsilon = k\varepsilon_0

has to be accounted for where k is the dielectric constant of the medium.

Energy stored in an electrostatic field distribution

One may take the equation for the electrostatic potential energy of a continuous charge distribution and put it in terms of the electrostatic field.

Since Gauss' law for electrostatic field in differential form states

\mathbf{\nabla}\cdot\mathbf{E} = \frac{\rho}{\varepsilon_0}

where

then,

U = \frac{1}{2}\int \limits_{\text{all space}} \rho(r) \Phi(r)d^3r
 = \frac{1}{2}\int \limits_{\text{all space}} \varepsilon_0(\mathbf{\nabla}\cdot{\mathbf{E}})\Phi(r)d^3r

so, now using the following divergence vector identity

 \nabla\cdot(\bold{A}{B}) = (\nabla\cdot\bold{A}){B} %2B \bold{A}\cdot(\nabla{B})  \Rightarrow (\nabla\cdot\bold{A}){B} = \nabla\cdot(\bold{A}{B}) - \bold{A}\cdot(\nabla{B})

we have

 U = \frac{\varepsilon_0}{2}\int \limits_{\text{all space}} \mathbf{\nabla}\cdot(\mathbf{E}\Phi) d^3r - \frac{\varepsilon_0}{2}\int \limits_{\text{all space}} (\mathbf{\nabla}\Phi)\cdot\mathbf{E} d^3r

using the divergence theorem and taking the area to be at infinity where \Phi(\infty) = 0

 U = \frac{\varepsilon_0}{2}\int \Phi\mathbf{E}\cdot dA - \frac{\varepsilon_0}{2}\int \limits_{\text{all space}} (-\mathbf{E})\cdot\mathbf{E} d^3r
 = \int \limits_{\text{all space}} \frac{1}{2}\varepsilon_0\left|{\mathbf{E}}\right|^2 d^3r.

So, the energy density, or energy per unit volume of the electrostatic field is:

 u_e = \frac{1}{2} \varepsilon_0 \left|{\mathbf{E}}\right|^2.

Energy in electronic elements

Some elements in a circuit can convert energy from one form to another. For example, a resistor converts electrical energy to heat, and a capacitor stores it in its electric field.

The total electric potential energy stored in a capacitor is given by

 U_E = \frac{1}{2}QV = \frac{1}{2} CV^2 = \frac{Q^2}{2C}

where C is the capacitance, V is the electric potential difference, and Q the charge stored in the capacitor.

References

  1. ^ a b Halliday, David; Resnick, Robert; Walker, Jearl (1997). "Electric Potential". Fundamentals of Physics (5th ed.). John Wiley & Sons. ISBN 0-471-10559-7. 
  2. ^ Electromagnetism (2nd edition), I.S. Grant, W.R. Phillips, Manchester Physics Series, 2008 ISBN 0 471 92712 0